| 1 |
francois |
941 |
Solution exercice 2 du chapitre deformation
|
| 2 |
|
|
tenseur des deformations en um/m
|
| 3 |
|
|
|
| 4 |
|
|
epsilon =
|
| 5 |
|
|
|
| 6 |
|
|
400 120 240
|
| 7 |
|
|
120 -200 -120
|
| 8 |
|
|
240 -120 160
|
| 9 |
|
|
|
| 10 |
|
|
Vecteurs et valeurs propes en um/m
|
| 11 |
|
|
|
| 12 |
|
|
V =
|
| 13 |
|
|
|
| 14 |
|
|
-0.2858 -0.4264 0.8582
|
| 15 |
|
|
0.8776 -0.4762 0.0556
|
| 16 |
|
|
0.3850 0.7690 0.5103
|
| 17 |
|
|
|
| 18 |
|
|
|
| 19 |
|
|
D =
|
| 20 |
|
|
|
| 21 |
|
|
-291.7243 0 0
|
| 22 |
|
|
0 101.2240 0
|
| 23 |
|
|
0 0 550.5003
|
| 24 |
|
|
|
| 25 |
|
|
Cisaillement maximal en um/m
|
| 26 |
|
|
|
| 27 |
|
|
gammamax =
|
| 28 |
|
|
|
| 29 |
|
|
842.2247
|
| 30 |
|
|
|
| 31 |
|
|
Direction du cisaillement maximal
|
| 32 |
|
|
|
| 33 |
|
|
direction =
|
| 34 |
|
|
|
| 35 |
|
|
0.2862 0.4666 0.4477
|
| 36 |
|
|
|
| 37 |
|
|
Normal plan du cisaillement max
|
| 38 |
|
|
|
| 39 |
|
|
n =
|
| 40 |
|
|
|
| 41 |
|
|
-0.4264 -0.4762 0.0556 |
