| 1 |
francois |
941 |
Solution exercice 2 du chapitre contrainte
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| 2 |
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tenseur des contraintes en MPa
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| 3 |
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| 4 |
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sigma =
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| 5 |
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| 6 |
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9 -30 0
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| 7 |
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-30 0 90
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| 8 |
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0 90 -81
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| 9 |
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| 10 |
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Vecteurs et valeurs propes en MPa
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| 11 |
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| 12 |
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V =
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| 13 |
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| 14 |
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-0.1103 -0.9124 -0.3941
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| 15 |
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-0.5513 -0.2737 0.7881
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| 16 |
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0.8270 -0.3041 0.4729
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| 17 |
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| 18 |
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| 19 |
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D =
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| 20 |
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| 21 |
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-141.0000 0 0
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| 22 |
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0 -0.0000 0
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| 23 |
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0 0 69.0000
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| 24 |
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| 25 |
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Vecteurs contraintes de la facette ABC en MPa
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| 26 |
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| 27 |
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vecteur_sigma =
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| 28 |
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| 29 |
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5.1429
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| 30 |
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51.4286
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| 31 |
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-61.7143
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| 32 |
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| 33 |
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Angle entre le vecteur contrainte et la normale a la face en degre
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| 34 |
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| 35 |
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beta =
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| 36 |
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| 37 |
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123.2031
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| 38 |
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| 39 |
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Contrainte normale en MPa
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| 40 |
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| 41 |
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sigman =
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| 42 |
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| 43 |
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-44.0816
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| 44 |
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| 45 |
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Contrainte de cisaillement en MPa
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| 46 |
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| 47 |
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tau =
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| 48 |
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| 49 |
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67.3558 |
